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Popular >

2x^2-7x+7>0

Solution

2 x^{2} - 7 x + 7 > 0

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

2 x^{2} - 7 x + 7 > 0

Complete the square

2 x^{2} - 7 x + 7 : 2 (x - \frac{7}{4})^{2} + \frac{7}{8}

2 (x - \frac{7}{4})^{2} + \frac{7}{8} > 0

Move

\frac{7}{8}

to the right side

2 (x - \frac{7}{4})^{2} > - \frac{7}{8}

Divide both sides by

2

(x - \frac{7}{4})^{2} > - \frac{7}{16}

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

(x+5)(2x-3)^5(x-7)^3*(3x+8)^2<0

(x + 5) (2 x - 3)^{5} (x - 7)^{3} \cdot (3 x + 8)^{2} < 0

(2x-3)^2>(2x+5)(2x-1)

(2 x - 3)^{2} > (2 x + 5) (2 x - 1)

1/((x+1))+2/((x+3))> 3/((x+2))

\frac{1}{( x + 1 )} + \frac{2}{( x + 3 )} > \frac{3}{( x + 2 )}

(-4)/((2+5x))<0

\frac{- 4}{( 2 + 5 x )} < 0

(x+5)(2x-3)^5(x-7)^3(3x+8)^2<0

(x + 5) (2 x - 3)^{5} (x - 7)^{3} (3 x + 8)^{2} < 0

Frequently Asked Questions (FAQ)

What is 2x^2-7x+7>0 ?
The solution to 2x^2-7x+7>0 is True for all x