What is ((x^2-1))/((x+3))<= 0 ?

The solution to ((x^2-1))/((x+3))<= 0 is x<-3\lor-1<= x<= 1

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((x^2-1))/((x+3))<= 0

\frac{( x ^{2} - 1 )}{( x + 3 )} \leq 0

x < - 3 or - 1 \leq x \leq 1

Interval Notation

(- \infty, - 3) \cup [- 1, 1]

Solution steps

\frac{x ^{2} - 1}{x + 3} \leq 0

Factor

\frac{x ^{2} - 1}{x + 3} : \frac{( x + 1 ) ( x - 1 )}{x + 3}

\frac{( x + 1 ) ( x - 1 )}{x + 3} \leq 0

Identify the intervals

x < - 3 or - 1 \leq x \leq 1

\frac{4}{( x + 2 )} \geq 0

x^{3} + 5 x^{2} + 4 x \geq 0

(2 - x) (x + 3) > 0

x, 2 (2 x - 1) > 4 x - 6 u

\frac{( x + 1 ) ( x - 1 ) ( x + 2 )}{( x ^{2} + 3 x + 2 ) ( x + 5 )} < 0

What is ((x^2-1))/((x+3))<= 0 ?
The solution to ((x^2-1))/((x+3))<= 0 is x<-3\lor-1<= x<= 1