What are the solutions to the equation 4x^2=121 ?

The solutions to the equation 4x^2=121 are x= 11/2 ,x=-11/2

Find the zeros of 4x^2=121

The zeros of 4x^2=121 are x= 11/2 ,x=-11/2

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4 x^{2} = 121

x = \frac{11}{2}, x = - \frac{11}{2}

Solution steps

4 x^{2} = 121

Divide both sides by

4

x^{2} = \frac{121}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{121}{4}, x = - \frac{121}{4}

\frac{121}{4} = \frac{11}{2}

- \frac{121}{4} = - \frac{11}{2}

x = \frac{11}{2}, x = - \frac{11}{2}

2 x + 3 < 4 x + 5 \leq 3 x + 7

2 x^{2} + 4 x^{2} = 42

7 (2 - x) \geq 28

3 x - 5 > 16

∣ 2 x + 13 ∣ < 15

What are the solutions to the equation 4x^2=121 ?
The solutions to the equation 4x^2=121 are x= 11/2 ,x=-11/2
Find the zeros of 4x^2=121
The zeros of 4x^2=121 are x= 11/2 ,x=-11/2