What is ((2x+3))/((3x-7))>= 1 ?

The solution to ((2x+3))/((3x-7))>= 1 is 7/3 <x<= 10

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((2x+3))/((3x-7))>= 1

\frac{( 2 x + 3 )}{( 3 x - 7 )} \geq 1

\frac{7}{3} < x \leq 10

Interval Notation

(\frac{7}{3}, 10]

Decimal Notation

2.33333 \dots < x \leq 10

Solution steps

\frac{2 x + 3}{3 x - 7} \geq 1

Rewrite in standard form

\frac{- x + 10}{3 x - 7} \geq 0

Identify the intervals

\frac{7}{3} < x \leq 10

(x - 2)^{4} \cdot (x - 3)^{3} \cdot (x - 4)^{2} \cdot (1 - x) \leq 0

\frac{( ( x - 1 ) ( x - 3 ) )}{( ( x + 1 ) ( x - 5 ) )} \geq 0

(x^{2} - 3) (x + 1) < 0

x^{2} - 17 < 0

\frac{( x - 9 ) ( x - 15 )}{( x - 12 )} \geq 0

What is ((2x+3))/((3x-7))>= 1 ?
The solution to ((2x+3))/((3x-7))>= 1 is 7/3 <x<= 10