What are the solutions to the equation (t-10)^2-16=0 ?

The solutions to the equation (t-10)^2-16=0 are t=14,t=6

Find the zeros of (t-10)^2-16=0

The zeros of (t-10)^2-16=0 are t=14,t=6

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(t - 10)^{2} - 16 = 0

t = 14, t = 6

Solution steps

(t - 10)^{2} - 16 = 0

Move

16

to the right side

(t - 10)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t - 10 = 16 : t = 14

Solve

t - 10 = - 16 : t = 6

The solutions to the quadratic equation are:

t = 14, t = 6

- \frac{2}{15} - (- \frac{1}{9})

(2 x^{2} - x - 1) (- x + 1) \geq 0

∣ 5 x - 3 ∣ \geq 17

0.5

8 - 2 (a + 1) = 9 + a

What are the solutions to the equation (t-10)^2-16=0 ?
The solutions to the equation (t-10)^2-16=0 are t=14,t=6
Find the zeros of (t-10)^2-16=0
The zeros of (t-10)^2-16=0 are t=14,t=6