What is 1/((3x+1))-1/((3x-1))>= 2 ?

The solution to 1/((3x+1))-1/((3x-1))>= 2 is -1/3 <x< 1/3

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1/((3x+1))-1/((3x-1))>= 2

\frac{1}{( 3 x + 1 )} - \frac{1}{( 3 x - 1 )} \geq 2

- \frac{1}{3} < x < \frac{1}{3}

Interval Notation

(- \frac{1}{3}, \frac{1}{3})

Decimal Notation

- 0.33333 \dots < x < 0.33333 \dots

Solution steps

\frac{1}{3 x + 1} - \frac{1}{3 x - 1} \geq 2

Rewrite in standard form

\frac{x ^{2}}{( 3 x + 1 ) ( 3 x - 1 )} \leq 0

Identify the intervals

- \frac{1}{3} < x < \frac{1}{3}

\frac{( x - 3 ) ( x - 4 )}{( 2 x ^{2} - 4 x + 5 )} > 0

(x^{2} - 2 x) (3 x - 6) \leq 0

\frac{( x - 1 )}{( x - 2 )} + \frac{( x + 1 )}{( 3 - x )} \leq 1

9 x^{2} - 20 x + 11 > 0

x^{2} \cdot (x - 2)^{4} \cdot (x - 3) \geq 0

What is 1/((3x+1))-1/((3x-1))>= 2 ?
The solution to 1/((3x+1))-1/((3x-1))>= 2 is -1/3 <x< 1/3