What is ((7-2k))/((4(-k)))<= 1 ?

The solution to ((7-2k))/((4(-k))) 0

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((7-2k))/((4(-k)))<= 1

\frac{( 7 - 2 k )}{( 4 ( - k ) )} \leq 1

k \leq - \frac{7}{2} or k > 0

Interval Notation

(- \infty, - \frac{7}{2}] \cup (0, \infty)

Decimal Notation

k \leq - 3.5 or k > 0

Solution steps

\frac{7 - 2 k}{4 ( - k )} \leq 1

Rewrite in standard form

\frac{- 7 - 2 k}{k} \leq 0

Identify the intervals

k \leq - \frac{7}{2} or k > 0

\frac{( 2 ( x - 4 ) )}{( ( x - 1 ) ( x - 7 ) )} \leq \frac{1}{( x - 2 )}

(x - 1) (x - 2) \cdot (x - 3)^{2} > 0

\frac{1}{( x + 1 )} > \frac{1}{( x - 2 )}

(x - 1)^{2} (x + 1)^{3} (x - 4) \geq 0

(x + 2) (x + 2) > x (x - 4)

What is ((7-2k))/((4(-k)))<= 1 ?
The solution to ((7-2k))/((4(-k)))<= 1 is k<=-7/2 \lor k>0