What are the solutions to the equation 0=2x^2-x-3 ?

The solutions to the equation 0=2x^2-x-3 are x= 3/2 ,x=-1

Find the zeros of 0=2x^2-x-3

The zeros of 0=2x^2-x-3 are x= 3/2 ,x=-1

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0 = 2 x^{2} - x - 3

x = \frac{3}{2}, x = - 1

Solution steps

0 = 2 x^{2} - x - 3

Switch sides

2 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 3) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 2}

x = \frac{- ( - 1 ) + 5}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 1 ) - 5}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 1

a^{2} + 14 a + 48 = 0

n - 5 \leq 6

\frac{n - 7}{n ^{2} - n - 42}

6 x^{2} - 5 x \leq 2 x + 3

5 (x - 6) - 6 (x - 5) = x + 5 - (x - 6)

What are the solutions to the equation 0=2x^2-x-3 ?
The solutions to the equation 0=2x^2-x-3 are x= 3/2 ,x=-1
Find the zeros of 0=2x^2-x-3
The zeros of 0=2x^2-x-3 are x= 3/2 ,x=-1