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Popular >

-2x^2+x-1<0

Solution

- 2 x^{2} + x - 1 < 0

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

- 2 x^{2} + x - 1 < 0

Complete the square

- 2 x^{2} + x - 1 : - 2 (x - \frac{1}{4})^{2} - \frac{7}{8}

- 2 (x - \frac{1}{4})^{2} - \frac{7}{8} < 0

Move

\frac{7}{8}

to the right side

- 2 (x - \frac{1}{4})^{2} < \frac{7}{8}

Multiply both sides by

- 1

2 (x - \frac{1}{4})^{2} > - \frac{7}{8}

Divide both sides by

2

(x - \frac{1}{4})^{2} > - \frac{7}{16}

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

x^{2} - 2 x < 1

x^{2} - 2 > 2 x + 1

(x+2)*x(x-4)<= 0

(x + 2) \cdot x (x - 4) \leq 0

((x^2-3x+4))/((x+5))< 1/3

\frac{( x ^{2} - 3 x + 4 )}{( x + 5 )} < \frac{1}{3}

4 m^{2} + 4 m - 8 > 0

Frequently Asked Questions (FAQ)

What is -2x^2+x-1<0 ?
The solution to -2x^2+x-1<0 is True for all x