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Popular >

(3x+1)^2+4x<9x^2+x-4

Solution

(3 x + 1)^{2} + 4 x < 9 x^{2} + x - 4

Solution

x < - \frac{5}{9}

+2

Interval Notation

(- \infty, - \frac{5}{9})

Decimal Notation

x < - 0.55555 \dots

Solution steps

(3 x + 1)^{2} + 4 x < 9 x^{2} + x - 4

Rewrite in standard form

9 x + 5 < 0

Move

5

to the right side

9 x < - 5

Divide both sides by

9

x < - \frac{5}{9}

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n^{2} < n

Frequently Asked Questions (FAQ)

What is (3x+1)^2+4x<9x^2+x-4 ?
The solution to (3x+1)^2+4x<9x^2+x-4 is x<-5/9