What is ((6+j^3))/((2-j^3)+8)< 3/10 ?

The solution to ((6+j^3))/((2-j^3)+8) \sqrt[3]{10}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((6+j^3))/((2-j^3)+8)< 3/10

\frac{( 6 + j ^{3} )}{( 2 - j ^{3} ) + 8} < \frac{3}{10}

Interval Notation

Decimal Notation

j < - 1.32147 \dots or j > 2.15443 \dots

Solution steps

\frac{6 + j ^{3}}{2 - j ^{3} + 8} < \frac{3}{10}

Rewrite in standard form

Identify the intervals

x^{2} - 2 x - 4 \leq 0

\frac{- 2}{x} < 0

(3 m - m^{2})^{2} > 0

\frac{4}{( x + 2 )} \geq 3 - x

(2 x - 6) (- 2 x + 8) > 0

What is ((6+j^3))/((2-j^3)+8)< 3/10 ?
The solution to ((6+j^3))/((2-j^3)+8)< 3/10 is j<-\sqrt[3]{30/13}\lor j>\sqrt[3]{10}