What is (n-3)^2-(n+4)(n-4)<43 ?

The solution to (n-3)^2-(n+4)(n-4) -3

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(n-3)^2-(n+4)(n-4)<43

(n - 3)^{2} - (n + 4) (n - 4) < 43

n > - 3

Interval Notation

(- 3, \infty)

Solution steps

(n - 3)^{2} - (n + 4) (n - 4) < 43

Rewrite in standard form

- n - 3 < 0

Move

3

to the right side

- n < 3

Multiply both sides by

- 1

n > - 3

12 x^{2} + x - 6 < 0

\frac{( 5 x - 8 )}{( x - 3 )} \geq 3

5 x - 3 x^{2} > 0

(x + 1)^{2} + 3 > 0

\frac{1}{( x - 3 )} \leq 4