What is ((2x-1))/((x+1))>= 6 ?

The solution to ((2x-1))/((x+1))>= 6 is -7/4 <= x<-1

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((2x-1))/((x+1))>= 6

\frac{( 2 x - 1 )}{( x + 1 )} \geq 6

- \frac{7}{4} \leq x < - 1

Interval Notation

[- \frac{7}{4}, - 1)

Decimal Notation

- 1.75 \leq x < - 1

Solution steps

\frac{2 x - 1}{x + 1} \geq 6

Rewrite in standard form

\frac{- 4 x - 7}{x + 1} \geq 0

Identify the intervals

- \frac{7}{4} \leq x < - 1

x^{2} - 9 x + 8 \leq 0

(x + 4)^{2} > 0

\frac{x}{( x - 3 )} \leq \frac{1}{x}

(x + 3)^{553} \cdot (3 x - 2)^{555} \cdot (7 - x)^{343} < 0

(x + 1) \cdot (4 - 2 x) < 0

What is ((2x-1))/((x+1))>= 6 ?
The solution to ((2x-1))/((x+1))>= 6 is -7/4 <= x<-1