What are the solutions to the equation y^2-10y=-14 ?

The solutions to the equation y^2-10y=-14 are y=5+sqrt(11),y=5-sqrt(11)

Find the zeros of y^2-10y=-14

The zeros of y^2-10y=-14 are y=5+sqrt(11),y=5-sqrt(11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 10 y = - 14

y = 5 + 11, y = 5 - 11

Solution steps

y^{2} - 10 y = - 14

Move

14

to the left side

y^{2} - 10 y + 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 14 = 211

y_{1, 2} = \frac{- ( - 10 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 2 11}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 2 11}{2 \cdot 1}

y = \frac{- ( - 10 ) + 2 11}{2 \cdot 1} : 5 + 11

y = \frac{- ( - 10 ) - 2 11}{2 \cdot 1} : 5 - 11

The solutions to the quadratic equation are:

y = 5 + 11, y = 5 - 11

f - 4 = 6 f + 26

9 < - 3 m < 24

(x + 2) (x + 3)

r p - 9 r + 9 p - 81

5 - n = 2

What are the solutions to the equation y^2-10y=-14 ?
The solutions to the equation y^2-10y=-14 are y=5+sqrt(11),y=5-sqrt(11)
Find the zeros of y^2-10y=-14
The zeros of y^2-10y=-14 are y=5+sqrt(11),y=5-sqrt(11)