What is (x-3)2>(x-7)(x+9) ?

The solution to (x-3)2>(x-7)(x+9) is -sqrt(57)<x<sqrt(57)

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(x-3)2>(x-7)(x+9)

(x - 3) 2 > (x - 7) (x + 9)

- 57 < x < 57

Interval Notation

(- 57, 57)

Decimal Notation

- 7.54983 \dots < x < 7.54983 \dots

Solution steps

(x - 3) \cdot 2 > (x - 7) (x + 9)

Rewrite in standard form

57 - x^{2} > 0

Move

57

to the right side

- x^{2} > - 57

Multiply both sides by

- 1

x^{2} < 57

For

u^{n} < a

, if

n

is even then

- 57 < x < 57

\frac{8 x}{x + 1} < 8

193 x^{2} - 7 x + 4 \leq 0

\frac{x}{( x + 4 )} - \frac{1}{( x + 1 )} \leq 0

2 + \frac{3}{x} + 1 - \frac{2}{x} > 0

\frac{( x + 3 )}{( x - 1 )} > x

What is (x-3)2>(x-7)(x+9) ?
The solution to (x-3)2>(x-7)(x+9) is -sqrt(57)<x<sqrt(57)