What is ((x^2-5x+4))/(((3-x)^3*(x+2)^4))<0 ?

The solution to ((x^2-5x+4))/(((3-x)^3*(x+2)^4)) 4

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((x^2-5x+4))/(((3-x)^3*(x+2)^4))<0

\frac{( x ^{2} - 5 x + 4 )}{( ( 3 - x ) ^{3} \cdot ( x + 2 ) ^{4} )} < 0

1 < x < 3 or x > 4

Interval Notation

(1, 3) \cup (4, \infty)

Solution steps

\frac{( x ^{2} - 5 x + 4 )}{( ( 3 - x ) ^{3} ( x + 2 ) ^{4} )} < 0

Identify the intervals

1 < x < 3 or x > 4

(x + 3) (5 - 2 x) + (2 x + 1) (x - 2) < \frac{x}{2}

\frac{( x ^{2} - 5 x + 6 )}{( x ^{2} - 7 x + 12 )} \leq 0

[x] < 2

7 x (x + 3) > 8

\frac{2}{( x - 3 )} - \frac{3}{( x + 2 )} < \frac{12}{( x ^{2} - x - 6 )}

What is ((x^2-5x+4))/(((3-x)^3*(x+2)^4))<0 ?
The solution to ((x^2-5x+4))/(((3-x)^3*(x+2)^4))<0 is 1<x<3\lor x>4