What is (((x+5)(x-8)))/((x-12))>0 ?

The solution to (((x+5)(x-8)))/((x-12))>0 is -5 12

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(((x+5)(x-8)))/((x-12))>0

\frac{( ( x + 5 ) ( x - 8 ) )}{( x - 12 )} > 0

- 5 < x < 8 or x > 12

Interval Notation

(- 5, 8) \cup (12, \infty)

Solution steps

\frac{( x + 5 ) ( x - 8 )}{x - 12} > 0

Identify the intervals

- 5 < x < 8 or x > 12

7 x + 5 x < x^{2} - 10

\frac{( x - 2 ) ^{2} ( x - 1 )}{( x - 3 )} \geq 0

\frac{1}{( n - 2 )} + \frac{1}{( n - 1 )} > \frac{1}{n}

(x - 2) (x - 3) (x + 2) (x + 3) > 0

x (9 x - 4) < (3 x + 2)^{2}

What is (((x+5)(x-8)))/((x-12))>0 ?
The solution to (((x+5)(x-8)))/((x-12))>0 is -5<x<8\lor x>12