What are the solutions to the equation 5x^2+20=0 ?

The solutions to the equation 5x^2+20=0 are x=2i,x=-2i

Find the zeros of 5x^2+20=0

The zeros of 5x^2+20=0 are x=2i,x=-2i

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5 x^{2} + 20 = 0

x = 2 i, x = - 2 i

Solution steps

5 x^{2} + 20 = 0

Move

20

to the right side

5 x^{2} = - 20

Divide both sides by

5

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

- 0.6 (8)^{2} + 4.8 (8)

\frac{10 !}{4 ! ( 10 - 4 ) !}

3 (w + 9) = 7 w - 1

x + x + 2 + x + 4 + x + 6 = - 28

4.5 (x - 9) = - 13.5

What are the solutions to the equation 5x^2+20=0 ?
The solutions to the equation 5x^2+20=0 are x=2i,x=-2i
Find the zeros of 5x^2+20=0
The zeros of 5x^2+20=0 are x=2i,x=-2i