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Popular >

x^2-3x+4>-2

Solution

x^{2} - 3 x + 4 > - 2

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

x^{2} - 3 x + 4 > - 2

Rewrite in standard form

x^{2} - 3 x + 6 > 0

Complete the square

x^{2} - 3 x + 6 : (x - \frac{3}{2})^{2} + \frac{15}{4}

(x - \frac{3}{2})^{2} + \frac{15}{4} > 0

Move

\frac{15}{4}

to the right side

(x - \frac{3}{2})^{2} > - \frac{15}{4}

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

\frac{- 1}{2 x} > 6

((x^3+x^2+x))/((9x^2-25))>= 0

\frac{( x ^{3} + x ^{2} + x )}{( 9 x ^{2} - 25 )} \geq 0

(5 - x) \cdot (2 x - 6) > 0

2x^3-3x^2+7x-3>0

2 x^{3} - 3 x^{2} + 7 x - 3 > 0

((x+1))/((x-1^2))<-1

\frac{( x + 1 )}{( x - 1 ^{2} )} < - 1

Frequently Asked Questions (FAQ)

What is x^2-3x+4>-2 ?
The solution to x^2-3x+4>-2 is True for all x