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Popular >

x^2+5x+12>0

Solution

x^{2} + 5 x + 12 > 0

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

x^{2} + 5 x + 12 > 0

Complete the square

x^{2} + 5 x + 12 : (x + \frac{5}{2})^{2} + \frac{23}{4}

(x + \frac{5}{2})^{2} + \frac{23}{4} > 0

Move

\frac{23}{4}

to the right side

(x + \frac{5}{2})^{2} > - \frac{23}{4}

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

(x^2-7x+12)/(2x^2+4x+5)> 1/2

\frac{x ^{2} - 7 x + 12}{2 x ^{2} + 4 x + 5} > \frac{1}{2}

\frac{4}{( x - 3 )} < 0

(((x-1)^2(x+1)^3))/((x^4(x-2)))<= 0

\frac{( ( x - 1 ) ^{2} ( x + 1 ) ^{3} )}{( x ^{4} ( x - 2 ) )} \leq 0

(x^2+3x+1)(x^2+3x-3)>= 0

(x^{2} + 3 x + 1) (x^{2} + 3 x - 3) \geq 0

(x^2+1)(x^2-2x+5)>= 0

(x^{2} + 1) (x^{2} - 2 x + 5) \geq 0

Frequently Asked Questions (FAQ)

What is x^2+5x+12>0 ?
The solution to x^2+5x+12>0 is True for all x