What is (((x-4)(x-3)))/((x-3))<= 0 ?

The solution to (((x-4)(x-3)))/((x-3))<= 0 is x<3\lor 3<x<= 4

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(((x-4)(x-3)))/((x-3))<= 0

\frac{( ( x - 4 ) ( x - 3 ) )}{( x - 3 )} \leq 0

x < 3 or 3 < x \leq 4

Interval Notation

(- \infty, 3) \cup (3, 4]

Solution steps

\frac{( x - 4 ) ( x - 3 )}{x - 3} \leq 0

Identify the intervals

x < 3 or 3 < x \leq 4

\frac{( 14 x )}{( x + 1 )} - \frac{( 9 x - 30 )}{( x - 4 )} < 0

\frac{1}{( 3 x - 2 )} \leq \frac{1}{( 3 x + 4 )}

n^{5} - n^{3} < 0

\frac{( ( x - 1 ) ^{2} \cdot ( x + 1 ) ^{3} )}{( x ^{4} \cdot ( x - 2 ) )} < 0

\frac{3 \cdot ( 1 - x )}{2 + 2 x - 1} > \frac{3 x - 1}{2}

What is (((x-4)(x-3)))/((x-3))<= 0 ?
The solution to (((x-4)(x-3)))/((x-3))<= 0 is x<3\lor 3<x<= 4