What is -(x-1)(x-3)>= 0 ?

The solution to -(x-1)(x-3)>= 0 is 1<= x<= 3

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-(x-1)(x-3)>= 0

- (x - 1) (x - 3) \geq 0

1 \leq x \leq 3

Interval Notation

[1, 3]

Solution steps

- (x - 1) (x - 3) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x - 1) (x - 3)) (- 1) \leq 0 \cdot (- 1)

Simplify

(x - 1) (x - 3) \leq 0

Identify the intervals

1 \leq x \leq 3

(x - 3) (x - 5) > 0

\frac{( 2 x - 1 )}{( x + 2 )} > 0

\frac{( 13 x - 4 )}{( 5 x + 7 )} > 0

(x - 7) (x - 2) > 0

x^{3} > - 2 x