What is the answer to 33=(8y-7)/2+(7y+2)/6 ?

The answer to 33=(8y-7)/2+(7y+2)/6 is y=7

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33=(8y-7)/2+(7y+2)/6

33 = \frac{8 y - 7}{2} + \frac{7 y + 2}{6}

y = 7

Solution steps

33 = \frac{8 y - 7}{2} + \frac{7 y + 2}{6}

Switch sides

\frac{8 y - 7}{2} + \frac{7 y + 2}{6} = 33

Multiply by LCM

3 (8 y - 7) + 7 y + 2 = 198

Expand

3 (8 y - 7) + 7 y + 2 : 31 y - 19

31 y - 19 = 198

Move

19

to the right side

31 y = 217

Divide both sides by

31

y = 7

10 y^{2} + 27 y + 18

x^{2} + 6 x - 55

x^{2} + 19 x - 20

8 \cdot 8

What is the answer to 33=(8y-7)/2+(7y+2)/6 ?
The answer to 33=(8y-7)/2+(7y+2)/6 is y=7
Solve for y: 33=(8y-7)/2+(7y+2)/6
The solution is y=7