What is ((2x+3))/((x-3))<= 4 ?

The solution to ((2x+3))/((x-3)) = 15/2

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((2x+3))/((x-3))<= 4

\frac{( 2 x + 3 )}{( x - 3 )} \leq 4

x < 3 or x \geq \frac{15}{2}

Interval Notation

(- \infty, 3) \cup [\frac{15}{2}, \infty)

Decimal Notation

x < 3 or x \geq 7.5

Solution steps

\frac{2 x + 3}{x - 3} \leq 4

Rewrite in standard form

\frac{- 2 x + 15}{x - 3} \leq 0

Identify the intervals

x < 3 or x \geq \frac{15}{2}

\frac{x}{( x + 1 ) + 2} \leq 0

\frac{1}{x ^{2}} < 4

\frac{( x - 3 )}{( x + 5 )} < 0

(\frac{( x + 3 )}{( 1 - 2 x )}) > 0

\frac{1}{x + 2} < \frac{3}{x - 3}

What is ((2x+3))/((x-3))<= 4 ?
The solution to ((2x+3))/((x-3))<= 4 is x<3\lor x>= 15/2