What is ((x^2))/((2x^2+4x+5))>0 ?

The solution to ((x^2))/((2x^2+4x+5))>0 is x 0

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((x^2))/((2x^2+4x+5))>0

\frac{( x ^{2} )}{( 2 x ^{2} + 4 x + 5 )} > 0

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

\frac{x ^{2}}{2 x ^{2} + 4 x + 5} > 0

Identify the intervals

x < 0 or x > 0

\frac{( ( x + 3 ) ( x - 1 ) )}{( x ^{2} \cdot ( x - 20 ) ^{3} )} \leq 0

(x + 1) (x - 1) (x - 3) > 0

(x^{2}) - 4 x + 3 < 0

(x - 1)^{4} > 0

\frac{x ^{3} ( x - 2 ) ( 5 - x )}{( x ^{2} - 4 ) ( x + 1 )} > 0

What is ((x^2))/((2x^2+4x+5))>0 ?
The solution to ((x^2))/((2x^2+4x+5))>0 is x<0\lor x>0