What is (3x+54)/((2x+3))<= 18 ?

The solution to (3x+54)/((2x+3)) = 0

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(3x+54)/((2x+3))<= 18

\frac{3 x + 54}{( 2 x + 3 )} \leq 18

x < - \frac{3}{2} or x \geq 0

Interval Notation

(- \infty, - \frac{3}{2}) \cup [0, \infty)

Decimal Notation

x < - 1.5 or x \geq 0

Solution steps

\frac{3 x + 54}{2 x + 3} \leq 18

Rewrite in standard form

\frac{x}{2 x + 3} \geq 0

Identify the intervals

x < - \frac{3}{2} or x \geq 0

3 x^{2} (x - 4)^{2} < 32 - 5 (x - 2)^{2}

x^{2} - 18 > 0

2 x^{2} + 3 x < 4

\frac{4}{( x - 2 )} > \frac{3}{( x + 5 )}

2 x^{3} - 3 x^{2} - 8 x - 3 \leq 0

What is (3x+54)/((2x+3))<= 18 ?
The solution to (3x+54)/((2x+3))<= 18 is x<-3/2 \lor x>= 0