What is ((2-2x))/((3x+5))<0 ?

The solution to ((2-2x))/((3x+5)) 1

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((2-2x))/((3x+5))<0

\frac{( 2 - 2 x )}{( 3 x + 5 )} < 0

x < - \frac{5}{3} or x > 1

Interval Notation

(- \infty, - \frac{5}{3}) \cup (1, \infty)

Decimal Notation

x < - 1.66666 \dots or x > 1

Solution steps

\frac{2 - 2 x}{3 x + 5} < 0

Factor

\frac{2 - 2 x}{3 x + 5} : \frac{- 2 ( x - 1 )}{3 x + 5}

\frac{- 2 ( x - 1 )}{3 x + 5} < 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 2 ( x - 1 ) ) ( - 1 )}{3 x + 5} > 0 \cdot (- 1)

Simplify

\frac{2 ( x - 1 )}{3 x + 5} > 0

Divide both sides by

2

\frac{\frac{2 ( x - 1 )}{3 x + 5}}{2} > \frac{0}{2}

Simplify

\frac{x - 1}{3 x + 5} > 0

Identify the intervals

x < - \frac{5}{3} or x > 1

\frac{( x \cdot 2 )}{( x - 3 )} < 0

(x - 3) > (x - 3) (x - 4)

\frac{3}{5 x - 1} > 2 - x

24 x^{4} + 2 x^{3} - 5 x^{2} - x \geq 0

4 x^{3} - 9 x^{2} - 11 x + 26 \geq 0

What is ((2-2x))/((3x+5))<0 ?
The solution to ((2-2x))/((3x+5))<0 is x<-5/3 \lor x>1