en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2-2x+3>0

Solution

2 x^{2} - 2 x + 3 > 0

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

2 x^{2} - 2 x + 3 > 0

Complete the square

2 x^{2} - 2 x + 3 : 2 (x - \frac{1}{2})^{2} + \frac{5}{2}

2 (x - \frac{1}{2})^{2} + \frac{5}{2} > 0

Move

\frac{5}{2}

to the right side

2 (x - \frac{1}{2})^{2} > - \frac{5}{2}

Divide both sides by

2

(x - \frac{1}{2})^{2} > - \frac{5}{4}

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

((2-3x))/((3-2x))>= 0

\frac{( 2 - 3 x )}{( 3 - 2 x )} \geq 0

((x+4))/((x^2+4x+4))>((x-2))/((x^2-4))

\frac{( x + 4 )}{( x ^{2} + 4 x + 4 )} > \frac{( x - 2 )}{( x ^{2} - 4 )}

(a^2)/((a^4+1))>= 1/2

\frac{a ^{2}}{( a ^{4} + 1 )} \geq \frac{1}{2}

x^3-4x^2+2<x^3-2x^2+1

x^{3} - 4 x^{2} + 2 < x^{3} - 2 x^{2} + 1

\frac{- 3}{- x + 7} > 0

Frequently Asked Questions (FAQ)

What is 2x^2-2x+3>0 ?
The solution to 2x^2-2x+3>0 is True for all x