en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-2x^2+x-1>0

Solution

- 2 x^{2} + x - 1 > 0

Solution

No Solution

Solution steps

- 2 x^{2} + x - 1 > 0

Complete the square

- 2 x^{2} + x - 1 : - 2 (x - \frac{1}{4})^{2} - \frac{7}{8}

- 2 (x - \frac{1}{4})^{2} - \frac{7}{8} > 0

Move

\frac{7}{8}

to the right side

- 2 (x - \frac{1}{4})^{2} > \frac{7}{8}

Multiply both sides by

- 1

2 (x - \frac{1}{4})^{2} < - \frac{7}{8}

Divide both sides by

2

(x - \frac{1}{4})^{2} < - \frac{7}{16}

If n is even,

u^{n} \geq 0

for all

u

No Solution for x \in R

Popular Examples

x^{2} + 18 < 5 x

\frac{x - 1}{x + 1} < x

x^3-6x^2+5x+12<0

x^{3} - 6 x^{2} + 5 x + 12 < 0

x^4(x-1)^3(x+2)^2(x-5)(x+6)^2<0

x^{4} (x - 1)^{3} (x + 2)^{2} (x - 5) (x + 6)^{2} < 0

((3x-5))/((x^2-4))>0

\frac{( 3 x - 5 )}{( x ^{2} - 4 )} > 0

Frequently Asked Questions (FAQ)

What is -2x^2+x-1>0 ?
The solution to -2x^2+x-1>0 is No Solution