What is ((x+1))/4+((x+2))/5 <= ((8x-1))/(20) ?

The solution to ((x+1))/4+((x+2))/5 <= ((8x-1))/(20) is x<=-14

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((x+1))/4+((x+2))/5 <= ((8x-1))/(20)

\frac{( x + 1 )}{4} + \frac{( x + 2 )}{5} \leq \frac{( 8 x - 1 )}{20}

x \leq - 14

Interval Notation

(- \infty, - 14]

Solution steps

\frac{( x + 1 )}{4} + \frac{( x + 2 )}{5} \leq \frac{( 8 x - 1 )}{20}

\frac{x + 1}{4} + \frac{x + 2}{5} \leq \frac{( 8 x - 1 )}{20}

Multiply by LCM

5 (x + 1) + 4 (x + 2) \leq 8 x - 1

Expand

5 (x + 1) + 4 (x + 2) : 9 x + 13

9 x + 13 \leq 8 x - 1

Move

13

to the right side

9 x \leq 8 x - 14

Move

8 x

to the left side

x \leq - 14

2 (2 x - 1) \geq \frac{1}{2}

2 - x > 3

3 + 2 y - 3 < 0

4 - 3 x < - (1 + 8 x)

x, 5 x + 4 y < - 16

What is ((x+1))/4+((x+2))/5 <= ((8x-1))/(20) ?
The solution to ((x+1))/4+((x+2))/5 <= ((8x-1))/(20) is x<=-14