What is ((x+1))/2+((x+3))/5 >((6x-1))/(10) ?

The solution to ((x+1))/2+((x+3))/5 >((6x-1))/(10) is x>-12

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((x+1))/2+((x+3))/5 >((6x-1))/(10)

\frac{( x + 1 )}{2} + \frac{( x + 3 )}{5} > \frac{( 6 x - 1 )}{10}

x > - 12

Interval Notation

(- 12, \infty)

Solution steps

\frac{( x + 1 )}{2} + \frac{( x + 3 )}{5} > \frac{( 6 x - 1 )}{10}

\frac{x + 1}{2} + \frac{x + 3}{5} > \frac{( 6 x - 1 )}{10}

Multiply by LCM

5 (x + 1) + 2 (x + 3) > 6 x - 1

Expand

5 (x + 1) + 2 (x + 3) : 7 x + 11

7 x + 11 > 6 x - 1

Move

11

to the right side

7 x > 6 x - 12

Move

6 x

to the left side

x > - 12

2 x + 6 > 20

3 (x - 2) < 4 x + 1

4 w - 5 < - 10 + 3 w

- (5 x + 2) < - (2 x + 4)

x, 2 x + y > 4

What is ((x+1))/2+((x+3))/5 >((6x-1))/(10) ?
The solution to ((x+1))/2+((x+3))/5 >((6x-1))/(10) is x>-12