What are the solutions to the equation y-y^2=0 ?

The solutions to the equation y-y^2=0 are y=0,y=1

Find the zeros of y-y^2=0

The zeros of y-y^2=0 are y=0,y=1

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y - y^{2} = 0

y = 0, y = 1

Solution steps

y - y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- y^{2} + y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 0 = 1

y_{1, 2} = \frac{- 1 \pm 1}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- 1 + 1}{2 ( - 1 )}, y_{2} = \frac{- 1 - 1}{2 ( - 1 )}

y = \frac{- 1 + 1}{2 ( - 1 )} : 0

y = \frac{- 1 - 1}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

y = 0, y = 1

4 m \leq - 32 and m + 28 > 23

- 9 x^{5} y^{3} (y)

∣ x + 7 ∣ - 6 = 8

4 (w - 1) + 7 = 5 (2 w - 3)

- 24 x - 36 y

What are the solutions to the equation y-y^2=0 ?
The solutions to the equation y-y^2=0 are y=0,y=1
Find the zeros of y-y^2=0
The zeros of y-y^2=0 are y=0,y=1