What is 10((x+1))/2+10((x+3))/5 >10((6x-1))/(10) ?

The solution to 10((x+1))/2+10((x+3))/5 >10((6x-1))/(10) is x>-12

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10((x+1))/2+10((x+3))/5 >10((6x-1))/(10)

10 \frac{( x + 1 )}{2} + 10 \frac{( x + 3 )}{5} > 10 \frac{( 6 x - 1 )}{10}

x > - 12

Interval Notation

(- 12, \infty)

Solution steps

10 \cdot \frac{( x + 1 )}{2} + 10 \cdot \frac{( x + 3 )}{5} > 10 \cdot \frac{( 6 x - 1 )}{10}

10 \cdot \frac{x + 1}{2} = 5 (x + 1)

10 \cdot \frac{x + 3}{5} = 2 (x + 3)

5 (x + 1) + 2 (x + 3) > 10 \cdot \frac{( 6 x - 1 )}{10}

Expand

5 (x + 1) + 2 (x + 3) : 7 x + 11

Expand

10 \cdot \frac{6 x - 1}{10} : 6 x - 1

7 x + 11 > 6 x - 1

Move

11

to the right side

7 x > 6 x - 12

Move

6 x

to the left side

x > - 12

\frac{( 1 - lo g _{4} ( x ) )}{( 1 + lo g _{2} ( x ) )} \leq \frac{1}{2}

\frac{( 3 x + 1 )}{7} - \frac{( 2 - 4 x )}{3} \geq \frac{( - 5 x - 4 )}{14} + \frac{( 7 x )}{6}

x - 4 < 4

\frac{x}{2 + 1} > x

x, 2 (y + 4) < - x

What is 10((x+1))/2+10((x+3))/5 >10((6x-1))/(10) ?
The solution to 10((x+1))/2+10((x+3))/5 >10((6x-1))/(10) is x>-12