What is solvefor c,cx^2+x+1>0 ?

The solution to solvefor c,cx^2+x+1>0 is c>(-x-1)/(x^2);\quad x 0

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solvefor c,cx^2+x+1>0

solve for

c, c x^{2} + x + 1 > 0

c > \frac{- x - 1}{x ^{2}}; x < 0 or x > 0

Solution steps

c x^{2} + x + 1 > 0

Move

x

to the right side

c x^{2} + 1 > - x

Move

1

to the right side

c x^{2} > - x - 1

Divide both sides by

x^{2}; x < 0 or x > 0

c > \frac{- x - 1}{x ^{2}}; x < 0 or x > 0

- 2 x > - 6

x - 7 < x

- 5 + 7 x > 9

x, x + 3 y < 2

14 x - 7 > 6 x + 9

What is solvefor c,cx^2+x+1>0 ?
The solution to solvefor c,cx^2+x+1>0 is c>(-x-1)/(x^2);\quad x<0\lor x>0