What is solvefor d,(d)((x+1))/(((x-1)^2))<1 ?

The solution to solvefor d,(d)((x+1))/(((x-1)^2)) -1

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solvefor d,(d)((x+1))/(((x-1)^2))<1

solve for

d, (d) \frac{( x + 1 )}{( ( x - 1 ) ^{2} )} < 1

d < \frac{( x - 1 ) ^{2}}{x + 1}; x \neq = 1, x > - 1

Solution steps

(d) \frac{( x + 1 )}{( ( x - 1 ) ^{2} )} < 1

Simplify

\frac{( x + 1 )}{( ( x - 1 ) ^{2} )} : \frac{x + 1}{( x - 1 ) ^{2}}

d \frac{x + 1}{( x - 1 ) ^{2}} < 1

Multiply both sides by

(x - 1)^{2}

d (x + 1) < (x - 1)^{2}; x \neq = 1

Divide both sides by

x + 1; x \neq = 1, x > - 1

d < \frac{( x - 1 ) ^{2}}{x + 1}; x \neq = 1, x > - 1

x - 2 < \frac{10 + x}{2}

15 - (3 x - 2) < 18 - (x + 4)

7 x < 2 x + 100

x, 3 x - y < 6

x, \frac{( x + 2 )}{( y - 5 )} \leq 2

What is solvefor d,(d)((x+1))/(((x-1)^2))<1 ?
The solution to solvefor d,(d)((x+1))/(((x-1)^2))<1 is d<((x-1)^2)/(x+1);\quad x\ne 1,x>-1