What is log_{10}(12)(x+9)>log_{10}(12144) ?

The solution to log_{10}(12)(x+9)>log_{10}(12144) is x>log_{12}(12144)-9

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log_{10}(12)(x+9)>log_{10}(12144)

lo g_{10} (12) (x + 9) > lo g_{10} (12144)

x > lo g_{12} (12144) - 9

Interval Notation

(lo g_{12} (12144) - 9, \infty)

Decimal Notation

x > - 5.21531 \dots

Solution steps

lo g_{10} (12) (x + 9) > lo g_{10} (12144)

Divide both sides by

lo g_{10} (12)

x + 9 > lo g_{12} (12144)

Move

9

to the right side

x > lo g_{12} (12144) - 9

l - 3 x + 1 < 7

2 (3 x - 4) + 2 > x - 16

\frac{( 2 x )}{4 + 8} < 20

3 x - 5 < 6 x + 10

3 - 2 x < 4 + 7 x + 3 (5 - 6 x)

What is log_{10}(12)(x+9)>log_{10}(12144) ?
The solution to log_{10}(12)(x+9)>log_{10}(12144) is x>log_{12}(12144)-9