What are the solutions to the equation (4x^2-9)+2=2 ?

The solutions to the equation (4x^2-9)+2=2 are x= 3/2 ,x=-3/2

Find the zeros of (4x^2-9)+2=2

The zeros of (4x^2-9)+2=2 are x= 3/2 ,x=-3/2

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(4 x^{2} - 9) + 2 = 2

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 1.5, x = - 1.5

Solution steps

(4 x^{2} - 9) + 2 = 2

Refine

4 x^{2} - 7 = 2

Move

7

to the right side

4 x^{2} = 9

Divide both sides by

4

x^{2} = \frac{9}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{4}, x = - \frac{9}{4}

\frac{9}{4} = \frac{3}{2}

- \frac{9}{4} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

10 - ∣ 2 x - 3 ∣ \geq 6

\frac{4 3}{3}

7 (x - 6) = 28

\frac{- 1}{2}

2 x^{2} = 6 x

What are the solutions to the equation (4x^2-9)+2=2 ?
The solutions to the equation (4x^2-9)+2=2 are x= 3/2 ,x=-3/2
Find the zeros of (4x^2-9)+2=2
The zeros of (4x^2-9)+2=2 are x= 3/2 ,x=-3/2