What is ((5x-5))/2 >((4x+20))/3 ?

The solution to ((5x-5))/2 >((4x+20))/3 is x> 55/7

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((5x-5))/2 >((4x+20))/3

\frac{( 5 x - 5 )}{2} > \frac{( 4 x + 20 )}{3}

x > \frac{55}{7}

Solution steps

\frac{( 5 x - 5 )}{2} > \frac{( 4 x + 20 )}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(5 x - 5) \cdot 3 > 2 (4 x + 20)

Expand

(5 x - 5) \cdot 3 : 15 x - 15

Expand

2 (4 x + 20) : 8 x + 40

15 x - 15 > 8 x + 40

Move

15

to the right side

15 x > 8 x + 55

Move

8 x

to the left side

7 x > 55

Divide both sides by

7

x > \frac{55}{7}

\frac{( b ) ( 2 ( x - 1 ) )}{5} \leq \frac{( 3 ( 2 + x ) )}{7}

23 x - 27 - 13 x < 129 - 6

3 (x - 5) + 4 \leq 4 x - 18

\frac{5 x + 1}{6} > \frac{2 - 2 x + 1}{3}

x > 57 + x

What is ((5x-5))/2 >((4x+20))/3 ?
The solution to ((5x-5))/2 >((4x+20))/3 is x> 55/7