What are the solutions to the equation 40x^2-1400x+12000=0 ?

The solutions to the equation 40x^2-1400x+12000=0 are x=20,x=15

Find the zeros of 40x^2-1400x+12000=0

The zeros of 40x^2-1400x+12000=0 are x=20,x=15

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40 x^{2} - 1400 x + 12000 = 0

x = 20, x = 15

Solution steps

40 x^{2} - 1400 x + 12000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1400 ) \pm ( - 1400 ) ^{2} - 4 \cdot 40 \cdot 12000}{2 \cdot 40}

(- 1400)^{2} - 4 \cdot 40 \cdot 12000 = 200

x_{1, 2} = \frac{- ( - 1400 ) \pm 200}{2 \cdot 40}

Separate the solutions

x_{1} = \frac{- ( - 1400 ) + 200}{2 \cdot 40}, x_{2} = \frac{- ( - 1400 ) - 200}{2 \cdot 40}

x = \frac{- ( - 1400 ) + 200}{2 \cdot 40} : 20

x = \frac{- ( - 1400 ) - 200}{2 \cdot 40} : 15

The solutions to the quadratic equation are:

x = 20, x = 15

3^{\frac{5}{3}}

\frac{2 - x}{x - 5} \geq - 2

x + 3 + 4 \geq 5

0. 3^{- 0.35}

2 \leq x + 5 < 9

What are the solutions to the equation 40x^2-1400x+12000=0 ?
The solutions to the equation 40x^2-1400x+12000=0 are x=20,x=15
Find the zeros of 40x^2-1400x+12000=0
The zeros of 40x^2-1400x+12000=0 are x=20,x=15