What is log_{10}(7)(6x)>7(8-4x) ?

The solution to log_{10}(7)(6x)>7(8-4x) is x>(28)/(3log_{10)(7)+14}

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log_{10}(7)(6x)>7(8-4x)

lo g_{10} (7) (6 x) > 7 (8 - 4 x)

x > \frac{28}{3 lo g _{10} ( 7 ) + 14}

Solution steps

lo g_{10} (7) (6 x) > 7 (8 - 4 x)

Expand

lo g_{10} (7) (6 x) : 6 lo g_{10} (7) x

Expand

7 (8 - 4 x) : 56 - 28 x

6 lo g_{10} (7) x > 56 - 28 x

Move

28 x

to the left side

6 lo g_{10} (7) x + 28 x > 56

Factor

6 lo g_{10} (7) x + 28 x : 2 (3 lo g_{10} (7) + 14) x

2 (3 lo g_{10} (7) + 14) x > 56

Divide both sides by

2 (3 lo g_{10} (7) + 14)

x > \frac{28}{3 lo g _{10} ( 7 ) + 14}

x, x + 9 < - y + 9

- 6 \leq \frac{- 9 + ( - n )}{4}

4 (- 3 i + 4) > - 1 (36 u + 16)

4 x + 5 \geq 2 x - 1

15 x - 9 + x - 5 < 6 x + 6

What is log_{10}(7)(6x)>7(8-4x) ?
The solution to log_{10}(7)(6x)>7(8-4x) is x>(28)/(3log_{10)(7)+14}