What is 1/5*(4x-1)-((2x))/3 >2+1/7*x ?

The solution to 1/5*(4x-1)-((2x))/3 >2+1/7*x is x<-231

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1/5(4x-1)-((2x))/3 >2+1/7x

\frac{1}{5} \cdot (4 x - 1) - \frac{( 2 x )}{3} > 2 + \frac{1}{7} \cdot x

x < - 231

Interval Notation

(- \infty, - 231)

Solution steps

\frac{1}{5} (4 x - 1) - \frac{( 2 x )}{3} > 2 + \frac{1}{7} x

\frac{1}{5} (4 x - 1) - \frac{2 x}{3} > 2 + \frac{1}{7} x

Multiply by LCM

21 (4 x - 1) - 70 x > 210 + 15 x

Expand

21 (4 x - 1) - 70 x : 14 x - 21

14 x - 21 > 210 + 15 x

Move

21

to the right side

14 x > 15 x + 231

Move

15 x

to the left side

- x > 231

Multiply both sides by

- 1

x < - 231

x - 5 > 13

9 n - 7 i > 3 (3 n - 7 u)

2 x - 5 > \frac{1}{2}

2 (x + 1) > 5 (x - 2)

\frac{4 x + 1}{3} < \frac{12 x - 3}{7}

What is 1/5*(4x-1)-((2x))/3 >2+1/7*x ?
The solution to 1/5*(4x-1)-((2x))/3 >2+1/7*x is x<-231