What are the solutions to the equation -6x^2-4x+2=0 ?

The solutions to the equation -6x^2-4x+2=0 are x=-1,x= 1/3

Find the zeros of -6x^2-4x+2=0

The zeros of -6x^2-4x+2=0 are x=-1,x= 1/3

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- 6 x^{2} - 4 x + 2 = 0

x = - 1, x = \frac{1}{3}

Solution steps

- 6 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 6 ) \cdot 2}{2 ( - 6 )}

(- 4)^{2} - 4 (- 6) \cdot 2 = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 ( - 6 )}, x_{2} = \frac{- ( - 4 ) - 8}{2 ( - 6 )}

x = \frac{- ( - 4 ) + 8}{2 ( - 6 )} : - 1

x = \frac{- ( - 4 ) - 8}{2 ( - 6 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = - 1, x = \frac{1}{3}

- 45 x^{3} - 5 x^{2}

- 3 x^{2} - 6 x + 9

(- \frac{2 ^{4}}{2 ^{2}})^{3}

x^{4 - 16}

2 x + 1 = x

What are the solutions to the equation -6x^2-4x+2=0 ?
The solutions to the equation -6x^2-4x+2=0 are x=-1,x= 1/3
Find the zeros of -6x^2-4x+2=0
The zeros of -6x^2-4x+2=0 are x=-1,x= 1/3