|x+1|>x-3

Solution

∣ x + 1 ∣ > x - 3

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

∣ x + 1 ∣ > x - 3

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

x < - 1 or x \geq - 1

Merge Overlapping Intervals

True for all x

∣ 2 x - 3 ∣ < x + 1

x^{2} - 4 x < 5, ∣ x + 1 ∣ < 3

\frac{( 3 x )}{4 - 2} < 8

∣ 19 + 3 x ∣ \geq 46

\frac{( x - 4 )}{5} < 4