What is |x^2-4|>x^2-4 ?

The solution to |x^2-4|>x^2-4 is -2<x<2

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|x^2-4|>x^2-4

x^{2} - 4 > x^{2} - 4

- 2 < x < 2

Solution steps

x^{2} - 4 > x^{2} - 4

Find positive and negative intervals

x \leq - 2, - 2 < x < 2, x \geq 2

Solve the inequality for each interval

No Solution or - 2 < x < 2

Merge Overlapping Intervals

- 2 < x < 2

x^{2} - 5 ∣ x ∣ + 6 \geq 0

x^{2} - 4 ∣ x ∣ + 3 < 0

∣ 4 (x - 1) + 10 ∣ \leq 22

∣ 3 x - 2 ∣ \geq ∣ x + 1 ∣

\frac{( x ^{2} - 5 x + 4 )}{( x ^{2} - 4 )} \leq 1