What are the solutions to the equation r^2=(1159)/(15pi) ?

The solutions to the equation r^2=(1159)/(15pi) are r=sqrt((1159)/(15pi)),r=-sqrt((1159)/(15pi))

Find the zeros of r^2=(1159)/(15pi)

The zeros of r^2=(1159)/(15pi) are r=sqrt((1159)/(15pi)),r=-sqrt((1159)/(15pi))

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r^{2} = \frac{1159}{15 π}

r = \frac{1159}{15 π}, r = - \frac{1159}{15 π}

Solution steps

r^{2} = \frac{1159}{15 π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{1159}{15 π}, r = - \frac{1159}{15 π}

(x^{\frac{1}{4}} y^{16})^{\frac{1}{2}}

k^{2} - 8 k + 13 = - 2

(\frac{256}{625})^{\frac{1}{4}}

(x - 1) (x + 3) < 0

9 a + 7 = 8 a - 6

What are the solutions to the equation r^2=(1159)/(15pi) ?
The solutions to the equation r^2=(1159)/(15pi) are r=sqrt((1159)/(15pi)),r=-sqrt((1159)/(15pi))
Find the zeros of r^2=(1159)/(15pi)
The zeros of r^2=(1159)/(15pi) are r=sqrt((1159)/(15pi)),r=-sqrt((1159)/(15pi))