What are the solutions to the equation k^2-8k+13=-2 ?

The solutions to the equation k^2-8k+13=-2 are k=5,k=3

Find the zeros of k^2-8k+13=-2

The zeros of k^2-8k+13=-2 are k=5,k=3

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k^{2} - 8 k + 13 = - 2

k = 5, k = 3

Solution steps

k^{2} - 8 k + 13 = - 2

Move

2

to the left side

k^{2} - 8 k + 15 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

k_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, k_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

k = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

k = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

k = 5, k = 3

(\frac{256}{625})^{\frac{1}{4}}

(x - 1) (x + 3) < 0

9 a + 7 = 8 a - 6

\frac{12 x ^{2} y ^{3} z}{6 x ^{3} y ^{2} z ^{2}}

\frac{1}{3} - \frac{1}{15}

What are the solutions to the equation k^2-8k+13=-2 ?
The solutions to the equation k^2-8k+13=-2 are k=5,k=3
Find the zeros of k^2-8k+13=-2
The zeros of k^2-8k+13=-2 are k=5,k=3