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Popular >

|((x+2))/5 |<1

Solution

\frac{( x + 2 )}{5} < 1

Solution

- 7 < x < 3

+1

Interval Notation

(- 7, 3)

Solution steps

\frac{x + 2}{5} < 1

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 1 < \frac{x + 2}{5} < 1

\frac{x + 2}{5} > - 1 and \frac{x + 2}{5} < 1

x > - 7 and x < 3

Merge Overlapping Intervals

- 7 < x < 3

Popular Examples

|((x^2-5x+4))/((x^2-4))|>= 1

\frac{( x ^{2} - 5 x + 4 )}{( x ^{2} - 4 )} \geq 1

|((x^2+12))/((7x))|>= 1

\frac{( x ^{2} + 12 )}{( 7 x )} \geq 1

((|x|-4))/((|x|-5))<= 0

\frac{( ∣ x ∣ - 4 )}{( ∣ x ∣ - 5 )} \leq 0

∣ x ∣ - ∣ x - 2 ∣ \geq 1

\frac{3 - x}{2} \leq 2

Frequently Asked Questions (FAQ)

What is |((x+2))/5 |<1 ?
The solution to |((x+2))/5 |<1 is -7<x<3