Solution

Solution

+1
Solution steps
Find positive and negative intervals
Solve the inequality for each interval
Merge Overlapping Intervals

Popular Examples

|5x-3|>-3d(|x-3|-2)>1|(4x+8)/8 |>39|y-8|-6>= 30|(-2x+9)(x-1)|<5|x-1|

Frequently Asked Questions (FAQ)

  • What is |x+2|-|x-1|<x ?

    The solution to |x+2|-|x-1|<x is -3<x<-1\lor x>3