What is x^2+2|x+3|-10<= 0 ?

The solution to x^2+2|x+3|-10<= 0 is -sqrt(17)+1<= x<= sqrt(5)-1

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x^2+2|x+3|-10<= 0

x^{2} + 2 ∣ x + 3 ∣ - 10 \leq 0

- 17 + 1 \leq x \leq 5 - 1

Solution steps

x^{2} + 2 ∣ x + 3 ∣ - 10 \leq 0

Find positive and negative intervals

x < - 3, x \geq - 3

Solve the inequality for each interval

- 17 + 1 \leq x < - 3 or - 3 \leq x \leq 5 - 1

Merge Overlapping Intervals

- 17 + 1 \leq x \leq 5 - 1

∣ x - 6 ∣ > x^{2} - 5 x + 9

∣ x - 1 ∣ < x^{2} + 1

x^{3} - x \leq x

\frac{1}{2} - \frac{( 5 x )}{3} \leq 5

\frac{( ∣ x + 2 ∣ + x )}{( x + 1 )} > 1

What is x^2+2|x+3|-10<= 0 ?
The solution to x^2+2|x+3|-10<= 0 is -sqrt(17)+1<= x<= sqrt(5)-1