What is (1+x^2)>= |1-x^2| ?

The solution to (1+x^2)>= |1-x^2| is True for all x

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(1+x^2)>= |1-x^2|

(1 + x^{2}) \geq 1 - x^{2}

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

1 + x^{2} \geq 1 - x^{2}

Find positive and negative intervals

x < - 1, - 1 \leq x \leq 1, x > 1

Solve the inequality for each interval

x < - 1 or - 1 \leq x \leq 1 or x > 1

Merge Overlapping Intervals

True for all x

∣ x + 1 ∣ + ∣ x - 4 ∣ > 7

∣ m - 1 ∣ > ∣ m + 3 ∣

\frac{1}{5 ∣ 10 x - 2 ∣} < 1

∣ 3 x - 2 ∣ > - 3

\frac{∣ x - 3 ∣}{∣ x + 1 ∣} < 1